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I have milk that contains 1 percent fat and milk that contains 4 percent fat. a customer wants a double latte made with 1/3 of a pint of 2 percent milk. how much of each type of milk should i use ?

  • MsEHolt: You should use 2/9 of a pint of the 1% milk and 1/9 of a pint of the 4% milk.

    Let x be the amount of 1% milk used.  1% = 1/100 = 0.01; this gives us 0.01x to represent this.

    We know that we will use the 4% milk to make up the rest of the 1/3 pint; this gives us 0.04(1/3-x).

    Together, they will make 1/3 pint of 2% milk, or 0.02(1/3)

    This gives us the equation 
    0.01x+0.04(1/3-x) = 0.02(1/3)

    Multiplying, we have
    0.01x+0.04/3-0.04x = 0.02/3

    We can multiply everything by 3 to eliminate the fractions:
    0.01x*3 + 0.04 - 0.04x*3 = 0.02
    0.03x + 0.04 - 0.12x = 0.02

    Combining like terms, we have
    -0.09x + 0.04 = 0.02

    Subtract 0.04 from both sides:
    -0.09x + 0.04 - 0.04 = 0.02 - 0.04
    -0.09x = -0.02

    Divide both sides by -0.09:
    -0.09x/-0.09 = -0.02/-0.09

    This gives us x = 2/9, so we will use 2/9 of a pint of the 1% milk.

    1/3 - 2/9 = 3/9 - 2/9 = 1/9; we will use 1/9 of a pint of the 4% milk.
  • oeerivona:

    The double lathe milk with 2 percent fat concentration, is made by

    considering the concentration and amount of each constituent.

    The amount of each type of milk to be used in the [tex]\dfrac{1}{3}[/tex] pint of double lathe

    are;

    • [tex]\dfrac{2}{9}[/tex] pint of the 1 percent fat milk and  [tex]\dfrac{1}{9}[/tex] pint of the 4 percent fat milk.

    Reasons:

    Let x represent the amount of the milk that contains 1 percent fat in the

    volume of the 2 percent fat milk.

    Therefore, we have;

    The amount of the 4 percent fat milk to be used = [tex]\dfrac{1}{3} - x[/tex]

    [tex]Amount \ of \ fat = \dfrac{1}{100} \times x + \dfrac{4}{100} \times \left (\dfrac{1}{3} - x\right) = \dfrac{2}{100} \times \dfrac{1}{3} = \dfrac{2}{300}[/tex]

    [tex]\dfrac{1}{100} \times x + \dfrac{4}{100} \times \left (\dfrac{1}{3} - x\right) = \dfrac{4 - 9 \cdot x}{300} = \dfrac{2}{300}[/tex]

    Therefore;

    4 - 9·x = 2

    4 - 2 = 9·x

    [tex]x = \dfrac{2}{9}[/tex]

    The amount of the 1 percent fat milk to be used for the double lathe, x = [tex]\dfrac{2}{9}[/tex]

    of a pint.

    The amount of the 4 percent fat milk to be used for the double lathe = [tex]\dfrac{1}{3} - x[/tex]

    Therefore;

    The mount of the 4 percent fat milk = [tex]\dfrac{1}{3} - \dfrac{2}{9} =\dfrac{1}{9}[/tex]

    The amount of the 4 percent fat milk to be used for the double lathe = [tex]\dfrac{1}{9}[/tex]

    pint.

    Learn more here:

    https://brainly.com/question/13220698

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