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an experimental container has volume of 13000 L has an internal pressure of 1.38 atm. if the pressure inside the container becomes 250 atm, what would the new volume have to be ? assume all other properties remain constant ?

  • kenmyna:

    The  new  volume  is 71.76  L


    calculation

     The new  volume  is  calculated using  the Boyle's  law  formula

    that  is  P1V1=P2V2  where,

    P1=1.38 atm

    V1= 13000  L

    P2  =250 atm

    V2= ?

    make V2  the   subject of the formula   by diving both side by P2

    V2= P1V1/ P2

    v2=( 1.38  atm  x 13000 L)  / 250 atm = 71.76 L



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