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An electric heating element is connected to a 110 V circuit and a current of 3.2 A is flowing through the element. How much energy is used up during a period of 5 hours by the element

  • olemakpadu: Energy, E is given by =  IVt

    Where E is Energy in Juoles.
    I is Current in Amperes,
    t is time in seconds,

    I = 3.2 A,    V = 110 V,    t = 5 hours = 5 *3600 seconds.  1 hour = 3600s

    E =  3.2 * 110 * 5 * 3600

    E = 6 336 000 Juoles

    E = 6.336 * 10^6 J  =  6.336 MJ
  • PutereDinu: [tex]V=110 \ V \\ I=3,2 \ A \\ t=5 \ h=18 \ 000 \ s \\ \boxed{E-?} \\ \bold{Solving:} \\ \boxed{E=V \cdot t \cdot I} \\ E=110 \ V \cdot 3,2 \ A \cdot 18 \ 000 \ s \\ \Rightarrow \boxed{E=6 \ 336 \ 000 \ J}[/tex]
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